(2y)(2y^2-1)=

Solution for (2y)(2y^2-1)= equation:

Simplifying
(2y)(2y2 + -1) = 0

Remove parenthesis around (2y)
2y(2y2 + -1) = 0

Reorder the terms:
2y(-1 + 2y2) = 0
(-1 * 2y + 2y2 * 2y) = 0
(-2y + 4y3) = 0

Solving
-2y + 4y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2y'.
2y(-1 + 2y2) = 0

Ignore the factor 2.
Subproblem 1
Set the factor 'y' equal to zero and attempt to solve:

Simplifying
y = 0

Solving
y = 0

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 0
Subproblem 2
Set the factor '(-1 + 2y2)' equal to zero and attempt to solve:

Simplifying
-1 + 2y2 = 0

Solving
-1 + 2y2 = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2y2 = 0 + 1
2y2 = 0 + 1

Combine like terms: 0 + 1 = 1
2y2 = 1

Divide each side by '2'.
y2 = 0.5

Simplifying
y2 = 0.5

Take the square root of each side:
y = {-0.707106781, 0.707106781}
Solution
y = {0, -0.707106781, 0.707106781}